SC DrillTechSC DrillTechSOLIDS CONTROL · DWM← Articles
Solids controlSeparation physics

Stokes' Law: Why Fine Drilled Solids Won't Settle Out

Ask why fine drilled solids keep circulating no matter how big your pits are, and the answer is one equation. Stokes' Law shows that below a certain size, gravity settling is so slow it is effectively zero — which is exactly why mechanical separation exists.

The physics in one line

A particle falling through a fluid reaches a steady speed where drag balances its buoyant weight. Stokes' Law gives that terminal velocity. Two things dominate it: the particle diameter, which enters squared, and the fluid viscosity, which fights settling. Halve the particle size and it settles four times slower; thicken the mud and it slows further still.

Why this kills the settling pit

Run the numbers on a fine drilled solid and the settling velocity comes out in millimetres per hour, not per second. In a pit with mud turning over in minutes, that particle never reaches the bottom — it re-circulates. That is the entire case for the shaker at the flowline and the centrifuge downstream: they apply screening and many hundreds of g so separation happens in seconds, not days.

The equation

Terminal settling velocity (SI units):

v = g · d² · (ρp − ρf) ÷ (18 · μ)

v = settling velocity (m/s); g = 9.81 m/s²; d = particle diameter (m); ρp, ρf = particle and fluid density (kg/m³); μ = fluid viscosity (Pa·s).

Worked example. A 30-micron drilled solid (d = 30×10−6 m, ρp = 2600) in mud of ρf = 1200 kg/m³ and μ = 0.03 Pa·s (30 cP): v = 9.81 × (30×10−6)² × (2600 − 1200) ÷ (18 × 0.03) = 2.3×10−5 m/s ≈ 0.023 mm/s ≈ 82 mm/hr. That particle drifts down under a hand-width per hour — it will never settle out of a circulating pit.
Reading the result

Because velocity scales with the square of diameter, colloidal and near-colloidal solids are essentially unremovable by settling or even by cyclone — the only real tools left are the high-g centrifuge and dilution. Catch solids coarse, at the shaker, while Stokes still favours you.

Common questions

Why can't a bigger settling pit fix fine solids?
Because fine-particle settling velocity is measured in millimetres per hour while pit residence time is measured in minutes. No practical pit is deep enough or slow enough for Stokes settling to remove sub-40-micron solids from an active system.

How does a centrifuge beat Stokes' Law?
It doesn't beat the law — it changes the input. A decanter applies two to three thousand g in place of one, and settling velocity scales directly with that acceleration, so separation that would take hours under gravity happens in a fraction of a second.

Share
LinkedInWhatsAppX

Related reading

SC DrillTech Rig IQ — field engineering platform for solids control and drilling-waste management

Want to run this on your own rig data?

Rig IQ runs this calculation live — enter your shift numbers and it returns the result, the interpretation and a report-ready output, with an AI engineering director reading the numbers with you. Grounded in API RP 13C · 13B · 13D.

Go deep in Rig IQ →

Need an independent assessment?

Independent rig evaluation, troubleshooting review, or solids-control performance check — measured against the operator standard you’ll be held to. Anything you share stays confidential to SC DrillTech.

Request an independent evaluation →